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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsElectric Field & ForceMedium2 minPYQ_2008

PhysicsMediumsingle choice

A thin conducting ring of radius $R$ is given a charge $+ Q$ . The electric field at the centre $O$ of the ring due to the charge on the part $AKB$ of the ring is $E$ . The electric field at the centre due to the charge on the part $ACDB$ of the ring is
NEET 2008 (Mains)

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Answer:

Solution:

$E_{0} \Rightarrow E_{A K B} + E_{A C D B} E_{A C D B} = 0 = 0 =^{(-)} E_{A K B} = - E (along K O) = E (along O K)$

Stream:NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:Electric Field & Force

⏱ 2mℹ️ Source: PYQ_2008

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