A charged particle of mass m and charge q is released from rest in a uniform electric field E. Neglecting the effect of gravity, choose the CORRECT statement(s) :-

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Force on the particle: F = qE, constant → (A) is correct.

Acceleration a = qE/m, so v = qEt/m and momentum p = qEt, which always increases → (B) is correct.

Kinetic energy: $K = \frac{1}{2} m v^{2} = \frac{1}{2} m (\frac{qEt}{m})^{2} = \frac{E ^{2} q ^{2} t ^{2}}{2 m}$ → (C) is correct.

The particle starts from rest and the force is along E, so it moves in a straight line, not a parabola → (D) is wrong.

Hence (A), (B) and (C).

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