Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsElectric Field & ForceMedium2 minPYQ_2017

PhysicsMediumsingle choice

Three charges are placed at the three vertices of an equilateral triangle of side $a$ as shown in the figure. The force experienced by the charge placed at the vertex $A$ in a direction normal to $B C$ is

Options:

Answer:

Solution:

Resultant force

$F^{'} = \sqrt{F^{2} + F^{2} + 2 F F \cos 120 °} = F$ $[∵ \cos 120 ° = \frac{- 1}{2}]$

Now, from figure

$F = \sqrt{F^{' 2} + F^{'' 2} + 2 F^{'} F^{''} \cos 90 °}$

Now, the force normal to $B C$ at vertex $A$ is

$F^{''} = \sqrt{F^{2} - F^{' 2}} = 0$ $(∵ F^{'} = F)$

Stream:BITSATSubject:PhysicsTopic:ElectrostaticsSubtopic:Electric Field & Force

⏱ 2mℹ️ Source: PYQ_2017

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