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PhysicsElectrostaticsGauss LawEasy2 minPYQ_2025

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A square loop of sides $a = 1 m$ is held normally in front of a point charge $q = 1 C$ . The flux of the electric field through the shaded region is $\frac{5}{p} \times \frac{1}{ε _{0}} \frac{Nm ^{2}}{C}$ , where the value of p is _____.

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Answer:

Solution:

Total flux through square $= \frac{q}{ϵ _{0}} (\frac{1}{6})$ Lets divide square is 8 equal parts. Flux is same for each part. $∴$ Flux through shaded portion is $\frac{5}{8}$ (Total flux) $= \frac{5}{8} \times \frac{q}{ϵ _{0}} \frac{1}{6} = \frac{5}{48} \frac{1}{ϵ _{0}}$ $∴$ required Ans. is 48

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:Gauss Law

⏱ 2mℹ️ Source: PYQ_2025

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