Physics - Electrostatics Question with Solution | TestHub

The potential at a distance $r$ due to a short dipole is $V_{dip}\left(r\right)=\frac{1}{4\pi {\epsilon }_{\circ }} \frac{\overrightarrow{p}·\hat{r}}{r^2}$, where $\overrightarrow{p}$=dipole moment.

Thus, $V_{dip}\left(r\right)$ is proportional to $\frac{1}{r^2}$.