Three charges + Q , q , + Q are placed respectively, at distance, 0 , d / 2 and d from the origin, on the x -axis. If the net force experienced by + Q , placed at x = 0 , is zero, then value of q is:

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For net force on charge placed at origin is given as
$\Rightarrow \frac{K {Q . q}^{}}{{(\frac{d}{2})}^{2}} + \frac{K Q^{2}}{d^{2}} = 0$ , where $K$ is a constant.
Solving the above equation, we get, $q = \frac{- Q}{4}$
Hence, the charge $q = - \frac{Q}{4}$ such that net force on the charge $+ Q$ placed at origin is zero.

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