An electric field, E = 6 2 i ^ + 6 j ^ + 8 k ^ passes through the surface of 4 m 2 area having unit vector n ^ = ( 6 2 i ^ + j ^ + k ^ ) . The electric flux for that surface is ______ Vm .

ϕ = E ⋅ A = ( 6 2 i ^ + 6 j ^ + 8 k ^ ) ⋅ 4 ( 6 2 i ^ + j ^ + k ^ ) = 6 4 × ( 4 + 6 + 8 ) = 12 Vm

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PhysicsElectrostaticsGauss LawEasy2 minPYQ_2024

PhysicsEasynumerical

An electric field, $E = \frac{2 i ^ + 6 j ^ + 8 k ^}{6}$ passes through the surface of $4 m^{2}$ area having unit vector $\overset{n}{^} = (\frac{2 i ^ + j ^ + k ^}{6})$ . The electric flux for that surface is ______ $Vm$ .

Answer:

12.00

Solution:

$ϕ = E \cdot A = (\frac{2 i ^ + 6 j ^ + 8 k ^}{6}) \cdot 4 (\frac{2 i ^ + j ^ + k ^}{6}) = \frac{4}{6} \times (4 + 6 + 8) = 12 Vm$

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:Gauss Law

⏱ 2mℹ️ Source: PYQ_2024

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