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PhysicsElectrostaticsElectric Field & ForceMedium2 minPYQ_2023

PhysicsMediumsingle choice

A $10 μ C$ charge is divided into two parts and placed at $1 cm$ distance so that the repulsive force between them is maximum. The charges of the two parts are:

Options:

Answer:

Solution:

Let the charges be $x μC, (q - x) μC$ , where $q = 10 μC$
The force between them is
$F = \frac{K x (q - x)}{r^{2}}$ .
For the force to be maximum,
$\frac{d F}{d x} = 0 \Rightarrow \frac{d F}{d x} = \frac{K (q - 2 x)}{r^{2}} = 0 \Rightarrow x = \frac{q}{2} = 5 μC$

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:Electric Field & Force

⏱ 2mℹ️ Source: PYQ_2023

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