Start Free Mock LoginAlready registered? Login here

Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsPotential & potential energyHard2 minPYQ_2009

PhysicsHardsingle choice

The electric potential at a point $(x, y, z)$ is given by $V = - x^{2} y - x z^{3} + 4$ The electric field $E$ at that point is :NEET 2009 (Mains)

Options:

Answer:

Solution:

$V E = - x^{2} y - x z^{3} + 4 = - V = - (\hat{i} \frac{δ}{δ x} + \hat{j} \frac{δ}{δy} + \hat{k} \frac{δ}{δz}) = (2 x y + z^{3}) \hat{i} + x^{2} \hat{j} + 3 x z^{2} + 4)$

Stream:NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:Potential & potential energy

⏱ 2mℹ️ Source: PYQ_2009

Doubts & Discussion

Loading discussions...