Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsGauss LawMedium2 minPYQ_2021

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A charge $q$ is placed at one corner of a cube as shown in figure. The flux of electrostatic field $\vec{E}$ through the shaded area is:

Answer:

Solution:

flux through cube $= \frac{q}{8 ϵ_{0}}$

flux through surfaces $A B E H, A D G H, A B C D$ will be zero

$ϕ (E F G H) = ϕ (D C F G) = ϕ (E B C F) = \frac{1}{3} (\frac{q}{8 ϵ_{0}})$

$= \frac{q}{24 ϵ_{0}}$

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:Gauss Law

⏱ 2mℹ️ Source: PYQ_2021

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