The electric field in a region is given by E → = 2 5 E 0 i ^ + 3 5 E 0 j ^ with E 0 = 4 . 0 × 10 3 N C - 1 . The flux of this field through a rectangular surface, area 0 . 4 m 2 parallel to the Y - Z plane is _______ N m 2 C - 1 .

ϕ = E x A ⇒ 2 5 × 4 × 10 3 × 0 . 4 = 640 N m 2 C - 1

Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsGauss LawEasy2 minPYQ_2021

PhysicsEasynumerical

The electric field in a region is given by $\vec{E} = \frac{2}{5} E_{0} \hat{i} + \frac{3}{5} E_{0} \hat{j}$ with $E_{0} = 4.0 \times 10^{3} N C^{- 1} .$ The flux of this field through a rectangular surface, area $0.4 m^{2}$ parallel to the $Y - Z$ plane is _______ $N m^{2} C^{- 1}$ .

Answer:

640.00

Solution:

$ϕ = E_{x} A \Rightarrow \frac{2}{5} \times 4 \times 10^{3} \times 0.4 = 640 N m^{2} C^{- 1}$

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:Gauss Law

⏱ 2mℹ️ Source: PYQ_2021

Doubts & Discussion

Loading discussions...