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Physics - Electrostatics Question with Solution | TestHub

PhysicsElectrostaticsPotential & potential energyEasy2 minPYQ_2011

PhysicsEasysingle choice

The electric potential $V$ at any point $(x, y, z)$ , all in metres in space is given by $V = 4 x^{2}$ volt. The electric field at the point $(1, 0, 2)$ in volt/metre isNEET 2011 (Mains)

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Solution:

We know that $E = - [\hat{i} \frac{\partial V}{\partial x} + \hat{j} \frac{\partial V}{\partial y} + k \frac{\partial V}{\partial z}]$ So $E = - \hat{i} \frac{\partial V}{\partial x} = - \hat{i} \frac{\partial}{\partial x} (4 x^{2}) = - 8 x \hat{i} Vm^{- 1} E_{(1, 0, 2)} = - 8 \hat{i} Vm^{- 1}$

Stream:NEETSubject:PhysicsTopic:ElectrostaticsSubtopic:Potential & potential energy

⏱ 2mℹ️ Source: PYQ_2011

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