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PhysicsElectrostaticsGauss LawEasy2 minPYQ_2020
PhysicsEasynumerical

An electric fieldE=4xi^-y2+1j^N/Cpasses through the box shown in figure. The flux of the electric field through surfacesABCDandBCGFare marked asϕIandϕIIrespectively. The difference betweenϕI-ϕIIis (inNm2/C) ____________.

Question diagram: An electric field E → = 4 x i ^ - y 2 + 1 j ^ N / C passes t
Answer:
48.00
Solution:

Flux viaABCD
ϕ1=E.dA=0
Flux viaBCEF
ϕ2=E.dA
ϕ2=E.A=4xi^-y2+1j^.4i^
=16x where, x=3
ϕ2=48N.m2C ϕ1-ϕ2=-48N.m2C

Stream:JEESubject:PhysicsTopic:ElectrostaticsSubtopic:Gauss Law
2mℹ️ Source: PYQ_2020

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