Two small positively charged spheres are suspended from a common point at the ceiling by the insulating light strings. The first sphere has mass m 1 and charge q 1 while the second one has mass m

Question

Two small positively charged spheres are suspended from a common point at the ceiling by the insulating light strings. The first sphere has mass $m_{1}$ and charge $q_{1}$ while the second one has mass $m_{2}$ and charge $q_{2}$ . The masses are in equilibrium. Match List-I with best possible entry in List- II.

Column I	Column II
(P) $ℓ_{1} > ℓ_{2}$ $θ_{1} = θ_{2}$	(1) $m_{1} < m_{2}$
(Q) $ℓ_{1} > ℓ_{2}$ $θ_{1} > θ_{2}$	(2) $m_{1} > m_{2}$
(R) $ℓ_{1} = ℓ_{2}$ $θ_{1} < θ_{2}$	(3) Relation between $m_{1}$ and $m_{2}$ can't be decided.
(S) $ℓ_{1} = ℓ_{2}$ $θ_{1} = θ_{2}$	(4) $m_{1} = m_{2}$
	(5) None of these

TestHub · Accepted Answer

(P) ( m 1 g ) ℓ 1 sin θ 1 m 1 ℓ 1 ℓ 1 m 1 = m 2 g ℓ 2 sin θ 2 = m 2 ℓ 2 > ℓ 2 < m 2 (Q) m g 1 sin θ 1 m 1 ℓ 1 sin θ 1 ∵ ℓ 1 sin θ 1 ∴ m 1 = m 2 g ℓ 2 sin θ 2 = m 2 ℓ 2 sin θ 2 > ℓ 2 sin θ 2 < m 2 (R) m 1 g ℓ 1 sin θ 1 = m 2 g ℓ 2 sin θ 2 m 1 sin θ 1 = m 2 sin θ 2 ∵ sin θ 2 > sin θ 1 ∴ m 1 > m 2 (S) m 1 g sin θ 1 = m 2 g ℓ 2 sin θ 1 ∵ ℓ 1 = ℓ 2 , sin θ 1 = sin θ 2 ∴ m 1 = m 2

Physics - Electrostatics Question with Solution | TestHub

Options:

Doubts & Discussion

JEE Advanced 2027 (Class 12)