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PhysicsElasticityMiscellaneousMedium2 minQB

PhysicsMediumsingle choice

A force of 400 kg-wt breaks a wire. The force that breaks a wire of double the cross-sectional area is:

Answer:

Solution:

The breaking stress is a property of the material, so the breaking force is $F_{b} = σ_{b} A$ .

$\frac{F _{2}}{F _{1}} = \frac{A _{2}}{A _{1}} = 2$

$F_{2} = 2 \times 400 = 800 kg-wt$

Stream:JEESubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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