Two identical wires ( A = 1 m m 2 ) support a block, each at 3 7 ∘ to horizontal. Cooling by 1 0 ∘ C requires what extra mass (kg) to keep J fixed? α = ∘ C 2 × 1 0 − 5 ; Y = 5 × 1 0 11 Pa .

Δ T = Y A α ( 10 ) = 100 N . Δ m g = 2Δ T sin 3 7 ∘ . With g = 10 , Δ m = 12 kg .

Start Free Mock LoginAlready registered? Login here

Physics - Elasticity Question with Solution | TestHub

PhysicsElasticityMiscellaneousMedium2 minQB

PhysicsMediumsingle choice

Two identical wires ( $A = 1 m m^{2}$ ) support a block, each at $3 7^{\circ}$ to horizontal. Cooling by $1 0^{\circ} C$ requires what extra mass (kg) to keep J fixed? $α = \frac{2 \times 1 0 ^{- 5}}{^{\circ} C}$ ; $Y = 5 \times 1 0^{11} Pa$ .

Options:

Answer:

Solution:

$Δ T = Y A α (10) = 100 N$ .

$Δ m g = 2Δ T sin 3 7^{\circ}$ .

With $g = 10$ , $Δ m = 12 kg$ .

Stream:JEESubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...