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PhysicsElasticityMiscellaneousHard2 minPYQ_2022
PhysicsHardnumerical

A string of area of cross-section4 mm2and length0.5is connected with a rigid body of mass2 kg. The body is rotated in a vertical circular path of radius0.5 m. The body acquires a speed of5 m s-1at the bottom of the circular path. Strain produced in the string when the body is at the bottom of the circle is _____×10-5. (Use Young's modulus1011 N m-2andg=10 m s-2)

Question diagram: A string of area of cross-section 4 mm 2 and length 0 . 5 is
Answer:
30.00
Solution:

Given here, A=4 mm2l=0.5 mm=2 kg and vb=5 m s-1.

Tension at the bottom of the circular motion is given by T=mg+mvb2R

Using Young's modulus, we have 

Strain produced in the string when the body is at the bottom of the circle is ll=TAY

=mg+mvb2lAY =20+2520.53×10-6×1011=30×10-5

Stream:JEESubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous
2mℹ️ Source: PYQ_2022

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