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Physics - Elasticity Question with Solution | TestHub

PhysicsElasticityMiscellaneousEasy2 minPYQ_2020

PhysicsEasysingle choice

A wire of natural length $l$ , Young's modulus Y and area of cross-section A is extended by $x$ . Then the energy stored in the wire is given by

Options:

Answer:

Solution:

Energy stored in the wire

$U = \frac{1}{2} Y \times (s t r a i n)^{2} \times v o l u m e$

or $U = \frac{1}{2} Y \times {(\frac{x}{l})}^{2} \times A l$

or $U = \frac{1}{2} \frac{{Y x}^{2}}{l} \times A$

or $U = \frac{1}{2} \frac{Y A}{l} x^{2}$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2020

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