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Physics - Elasticity Question with Solution | TestHub

PhysicsElasticityMiscellaneousMedium2 minQB

PhysicsMediumnumerical

A steel wire of length 4.5 m and a copper wire of length 3.5 m are stretched same amount under a given load. If ratio of Young's moduli of steel to that of copper is $\frac{12}{7}$ , then what is the ratio of cross sectional area of steel wire to copper wire?

Answer:

0.75

Solution:

Ans (0.75)

$Y_{S} = \frac{F / A _{S}}{Δ ℓ / ℓ _{S}}$ , $Y_{C} = \frac{F / A _{C}}{Δ ℓ / ℓ _{C}}$

$\frac{A _{S}}{A _{C}} = \frac{Y _{C}}{Y _{S}} \times \frac{ℓ _{S}}{ℓ _{C}} = \frac{7}{12} \times \frac{4.5}{3.5} = 0.75$

Stream:JEESubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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