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PhysicsElasticityMiscellaneousMedium2 minQB

PhysicsMediuminteger

Two steel wires of radii $r$ and $2 r$ are connected together end to end and tied to a wall as shown. The force stretches the combination by $\frac{27}{4} mm$ . How far does the junction point A move (in mm )?

Answer:

Solution:

$\frac{F}{A _{1}} = y \frac{Δ ℓ _{1}}{2 ℓ}$

$\frac{F}{A _{2}} = y \frac{Δ ℓ _{2}}{ℓ}$

$Δ ℓ_{1} + Δ ℓ_{2} = \frac{27}{4} mm$

$\frac{2 F ℓ}{A _{1} y} + \frac{F ℓ}{4 A _{1} y} = \frac{27}{4} mm$

Stream:JEESubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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