A ball falling in a lake of 200 m shows a decrease of 0.1 % in its volume. The Bulk modulus of elasticity of the material of the ball is (take g = 10 m s - 2 )

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TestHub · Accepted Answer

We know that pressure difference between surface point and a point at depth

$Δ P = h d g$

$\Rightarrow ∆ P = 200 \times 1 0^{3} \times 10$

$\Rightarrow ∆ P = 2 \times 1 0^{6} N m^{- 2}$

Bulk modulus $K = - \frac{Δ P}{\frac{Δ V}{V}}$

$K = - \frac{2 \times 1 0^{6}}{(- \frac{0.1}{100})}$

$K = 2 \times 1 0^{9} N m^{- 2}$

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