A 3.2 m steel wire of diameter 1.2 mm stretches 1.6 mm . Its modulus is 2.0 × 1 0 11 Pa . The load mass is closest to:

A = π ( 0.6 × 1 0 − 3 ) 2 . m = gL Y A Δ L ≃ 11.3 kg for g = 10 . Closest option: 12 kg .

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A $3.2 m$ steel wire of diameter $1.2 mm$ stretches $1.6 mm$ . Its modulus is $2.0 \times 1 0^{11} Pa$ . The load mass is closest to:

Answer:

Solution:

$A = π (0.6 \times 1 0^{- 3})^{2}$ .

$m = \frac{Y A Δ L}{gL} ≃ 11.3 kg$ for $g = 10$ .

Closest option: $12 kg$ .

Stream:JEESubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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