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Physics - Elasticity Question with Solution | TestHub

PhysicsElasticityMiscellaneousEasy2 minPYQ_2018

PhysicsEasysingle choice

Two wires are made of the same material and have the same volume. The first wire has cross-sectional area $A$ and the second wire has cross-sectional area $3 A .$ If the length of the first wire is increased by $∆ l$ on applying a force $F,$ how much force is needed to stretch the second wire by the same amount?NEET 2018

Options:

Answer:

Solution:

$Y = \frac{F l}{A ∆ l}$

$∵ V = A l s o l = \frac{V}{A}$

$F = \frac{Y A ∆ l}{l} = \frac{Y A^{2} ∆ l}{V}$

$\frac{F_{1}}{F_{2}} = {(\frac{A_{1}}{A_{2}})}^{2} \Rightarrow \frac{F}{F_{2}} = {(\frac{A}{3 A})}^{2} = \frac{1}{9}$

$F_{2} = 9 F_{1} = 9 F$

Stream:NEETSubject:PhysicsTopic:ElasticitySubtopic:Miscellaneous

⏱ 2mℹ️ Source: PYQ_2018

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