Physics - Current Electricity Question with Solution | TestHub

The plain wire AB shorts A and B, bypassing the $4\Omega$ and $6\Omega$ resistors, so the circuit is just the $2\Omega$ resistor across the 20 V battery.

Current $I=\frac{20}{2}=10$ A and power supplied $P=20\times 10=200$ W - (A) correct, (B) wrong.

Both the $4\Omega$ and $6\Omega$ carry zero p.d., hence equal p.d. - (C) correct; the wire AB carries the full 10 A, so (D) is wrong.