The figure below shows a wheatstone bridge with resistors $P$ and $Q$ having almost equal resistance. When $R = 400 Ω$ , the bridge is in balanced condition. If on interchanging $P$ and $Q$ , the bridge is again balanced for $R = 405 Ω$ , then the value of $X$ is

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Initially, P Q = 400 x Once we interchange P and Q , we get Q P = 405 X ⇒ P Q × Q P = 400 × 405 X 2 ⇒ X = 400 × 405 ≈ 402 . 5 Ω

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