Physics - Current Electricity Question with Solution | TestHub

Equivalent resistance between A and B= series combination of $1\Omega$ and $2\Omega$ in parallel with $3\Omega$ resistor.
$\frac{1}{\mathrm{R}}=\frac{1}{3}+\frac{1}{3}=\frac{2}{3}$ or $\mathrm{R}=1.5\Omega$ $\therefore$ Current in the circuit is $\mathrm{I}=\mathrm{V}/\mathrm{R}=1.5/1.5=$ $1\mathrm{A}$. Since the resistance in $\mathrm{arm}\mathrm{ACB}=$ resistance in $\mathrm{arm}\mathrm{AB}=3\Omega$, the current divides equally in the two arms. Hence the current through the $3\Omega$ resistor $=\mathrm{I}/2=0.5\mathrm{A}$.