Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityCircuit AnalysisEasy2 minQB

PhysicsEasynumerical

The voltage across the $10Ω$ resistor in the given circuit is $x$ volt.

The value of $x$ to the nearest integer is _____.

Answer:

70.00

Solution:

$R_{e q_{1}} = \frac{50 \times 20}{70} = \frac{100}{7}$

$R_{e q} = \frac{170}{7}$
$v_{1} = [\frac{\frac{170}{170}}{7}] \times 10 = 70 V$

$= 70.00$

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Circuit Analysis

⏱ 2mℹ️ Source: QB

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