Physics - Current Electricity Question with Solution | TestHub

The resistance of any bulb$={\text{V}}^2/P$

Current through ammeter at shown position$=3i_1$

current in any $1$ bulb$=i_1=\frac{V}{R}=\frac{V}{V^2/P}$ $=\frac{P}{V}=\frac{100}{220}$

Through ammeter, $\Rightarrow i_{net}=3i_1=\frac{300}{220}$ $=1.35\text{A}$