Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical PowerMedium2 minQB

PhysicsMediumsingle choice

If in the circuit, power dissipation is $150 W$ , then $R$ is

Answer:

Solution:

$W = \frac{V ^{2}}{R _{net}}; 150 = \frac{( 15 ) ^{2}}{R} + \frac{( 15 ) ^{2}}{2} \Rightarrow R = 6Ω$

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Electrical Power

⏱ 2mℹ️ Source: QB

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