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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityCircuit AnalysisHard2 minQB

PhysicsHardsingle choice

The four arms of a Wheatstone bridge have resistances as shown in the figure. A galvanometer of $15Ω$ resistance is connected across BD. Calculate the current through the galvanometer when a potential difference of $10 V$ is maintained across AC.

Options:

Answer:

Solution:

$\frac{x - 10}{100} + \frac{x - y}{15} + \frac{x - 0}{10} = 0$

$53 x - 20 y = 30 \dots\dots (1)$

$\frac{y - 10}{60} + \frac{y - x}{15} + \frac{y - 0}{5} = 0$

$17 y - 4 x = 10 \dots\dots (2)$

on solving $(1) & (2)$

$x = 0.865$

$y = 0.792$

$Δ V = 0.073 R = 15Ω$

$\Rightarrow i = 4.87 mA$

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Circuit Analysis

⏱ 2mℹ️ Source: QB

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