Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityMiscellaneousMedium2 minQB

PhysicsMediumsingle choice

A circular portion is cut of a disc of thickness $t$ , its resistivity is $ρ$ and radii of disc are $a$ and $b (b > a)$ . A potential difference is maintained between outer and inner cylindrical surfaces of the disc. What is resistance of the disc?

Options:

Answer:

Solution:

$dR = \frac{ρ dr}{2 π rt}$ (All in series)

$∴ R = \int_{a}^{b} \frac{ρ dr}{2 π rt} = \frac{ρ}{2 π t} ℓ n (\frac{b}{a}) .$

Stream:BoardsSubject:PhysicsTopic:Current ElectricitySubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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