Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical instrumentMedium2 minQB

PhysicsMediumsingle choice

If $n$ represents the actual number of deflections in a converted galvanometer of resistance $G$ and shunt resistance $S$ . Then the total current $I$ when its figure of merit is $K$ will be

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Answer:

Solution:

Let current through galvanometer be $I_{G}$ and current through shunt resistance be $I - I_{G}$ .

Given figure of merit $K = \frac{I _{G}}{n}$

Then, total current, $I = \frac{I _{G} ( G + S )}{S}$

$I = \frac{n K ( G + S )}{S}$

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Electrical instrument

⏱ 2mℹ️ Source: QB

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