Physics - Current Electricity Question with Solution | TestHub

The resistance in each branch is $6\Omega$. They are in parallel. So, net resistance is $R^{\prime }=\frac{6}{2}=3\Omega$.

The total current flowing through the loop,

$I=\frac{V}{R^{\prime }}=\frac{9\mathrm{V}}{3\Omega }=3\text{A}$

Thus, through each branch the current is $1.5\text{A}$.

Hence, the voltage difference across the points is

$V_A-V_B=\left(4\times 1.5\right)-\left(2\times 1.5\right)=3\mathrm{V}$