If charge flow in a circuit is given by q = ( t + t 1 ) C then current in circuit at t = 2 sec will be

q = t + t 1 i = d t d q = 1 − t 2 1 i ( 2 ) = 1 − 4 1 = 4 3 A Hence option C.

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If charge flow in a circuit is given by $q = (t + \frac{1}{t}) C$ then current in circuit at $t = 2 sec$ will be

Answer:

Solution:

$q = t + \frac{1}{t}$

$i = \frac{d q}{d t} = 1 - \frac{1}{t ^{2}}$

$i (2) = 1 - \frac{1}{4} = \frac{3}{4} A$

Hence option C.

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Miscellaneous

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