Two cells are connected in opposition as shown. Cell $E_{1}$ is of $8 V$ emf and $2Ω$ internal resistance; the cell $E_{2}$ is of $2 V$ emf and $4Ω$ internal resistance. The terminal potential difference of cell $E_{2}$ is ______ $V$ .

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Current in circuit, I = 2 + 4 8 − 2 ​ = 6 6 ​ = 1 A Applying Kirchhoff's law from C to B , V C ​ − 2 − 4 × 1 = V B ​ ⇒ V C ​ − V B ​ = 6 V

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