Physics - Current Electricity Question with Solution | TestHub

When the resistor$R$is connected in parallel with voltmeter, the effective resistance in the circuit decreases because$\left(\frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}\right)$

Therefore current,$I=\frac{V}{R}$increases.

As$I$increases, potential across$R$increases and hence potential across voltmeter decreases. Hence reading of voltmeter decreases.