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PhysicsCurrent ElectricityCircuit AnalysisMedium2 minPYQ_2013

PhysicsMediumsingle choice

In the circuit shown in figure potential difference between points $A$ and $B$ is $16 V$ . the current passing through $2Ω$ resistance will be

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Solution:

$∴ 4 i_{1} + 2 (i_{1} + i_{2}) - 3 + 4 i_{1} = 16 V$ Using Kirchhoff's second law in the closed loop we have $9 - i_{2} - 2 (i_{1} + i_{2}) = 0$ Solving equations (i) and (ii), we get $i_{1} = 1.5 A$ and $i_{2} = 2 A$ $∴$ current through $2 W$ resistor $= 2 + 1.5 = 3.5 A$

Stream:BITSATSubject:PhysicsTopic:Current ElectricitySubtopic:Circuit Analysis

⏱ 2mℹ️ Source: PYQ_2013

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