A wire of length 25 m and cross-sectional area 5 mm 2 having resistivity of 2 × 1 0 − 6 Ω m is bent into a complete circle. The resistance between diametrically opposite points will be

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​ L = 25 m , A = 5 mm 2 = 5 × 1 0 − 6 m 2 ρ = 2 × 1 0 − 6 Ω m R wire ​ = A ρ L ​ = 5 × 1 0 − 6 2 × 1 0 − 6 × 25 ​ = 10 R eq ​ = 4 R ​ = 4 10 ​ = 2.5Ω ​ Answer does not match with NTA option.

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