Physics - Current Electricity Question with Solution | TestHub

If the resistance of the wire is R, then each arm of the square has a resistance of $\frac{R}{4}$. Accordingly. The resistance of segments DE and EC are $R_{DE}=R_{EC}=\frac{R}{8}$. We can draw the resultant circuit as follows:

Hence,

$\frac{1}{R_{eq}}=\frac{8}{R}+\frac{8}{7R}$
$\frac{1}{R_{eq}}=\frac{56+8}{7R}$
$R_{eq}=\frac{7R}{64}$