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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityCircuit AnalysisEasy2 minPYQ_2020

PhysicsEasysingle choice

The ammeter reading in the given circuit of Fig. is -

Options:

Answer:

Solution:

$E_{e q} = \frac{3 \times 1 + 6 \times 2}{1 + 2} = 5 V, r_{e q} = \frac{2 \times 1}{2 + 1} = \frac{2}{3} Ω$

$I = \frac{5}{10 + 2 / 3} = \frac{15}{32} A$

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Current ElectricitySubtopic:Circuit Analysis

⏱ 2mℹ️ Source: PYQ_2020

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