Physics - Capacitor Question with Solution | TestHub

$$c_1=\frac{(A/2){\epsilon }_0}{d/2}=\frac{A{\epsilon }_0}{d},c_2=K\frac{A{\epsilon }_0}{d},c_3=K\frac{A{\epsilon }_0}{2d}$$
$$\therefore c_{eq.}=\frac{c_1\times c_2}{c_1+c_2}+c_3=\frac{(3+\mathrm{K})\mathrm{K}A{\epsilon }_0}{2d(\mathrm{K}+1)}$$ $(\because C_1$ and $C_2$ are in series and resultant of these two in parallel with $C_3$ )