Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityMiscellaneousHard2 minQB

PhysicsHardnumerical range

Passage / Comprehension

The current I through a rod of a certain metallic oxide is given by $I = 0.2 V^{5/2}$ , where V is the potential difference across it. The rod is connected in series with a resistance to a 6 V battery of negligible internal resistance. What value should the series resistance(in SI units) have so that :

The power dissipated in the rod is twice that dissipated in resistance.

Answer:

0.31

Solution:

(ii) $P_{ro d} = 2 P_{res i s t a n ce}$

$V_{1} I = 2 I^{2} R$

Stream:BoardsSubject:PhysicsTopic:Current ElectricitySubtopic:Miscellaneous

⏱ 2mℹ️ Source: QB

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