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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityElectrical PowerEasy2 minPYQ_2020

PhysicsEasysingle choice

A $4 μF$ capacitor is charged to $400 V$ and then its plates are joined through a resistance of $1 kΩ$ . The heat produced in the resistance is

Options:

Answer:

Solution:

The energy stored in the capacitor

$= \frac{1}{2} {CV}^{2} = \frac{1}{2} \times 4 \times 10^{- 6} \times 400 \times 400 = 0.32 J$

This energy will be converted into heat in the resistor.

Stream:NTA_ABHYAS_NEETSubject:PhysicsTopic:Current ElectricitySubtopic:Electrical Power

⏱ 2mℹ️ Source: PYQ_2020

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