The current flowing through the 1Ω resistor is 10 n A. The value of n is _________

2 y − 5 + 2 y − 0 + 1 y − x + 10 = 0 y − 5 + y + 2 y − 2 x + 20 = 0 4 y − 2 x + 15 = 0 … . ( (i) 4 x − 5 + 4 x − 0 + 1 x − 10 − y = 0 x − 5 + x + 4 x − 40 − 4 y = 0 6 x − 4 y − 45 = 0 .. ( i ) 4 x − 30 = 0 − 2 x + 4 y + 15 = 0.. ( ii ) x = 2 15 &4 y − 15 + 15 = 0 y = 0 i = 1 y − x + 10 i = 1 0 − 7.5 + 10 i = 2.5 A = 10 n A n = 25

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Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityCircuit AnalysisHard2 minQB

PhysicsHardnumerical

The current flowing through the $1Ω$ resistor is $\frac{n}{10}$ A. The value of $n$ is _________

Answer:

25.00

Solution:

$\frac{y - 5}{2} + \frac{y - 0}{2} + \frac{y - x + 10}{1} = 0 y - 5 + y + 2 y - 2 x + 20 = 0 4 y - 2 x + 15 = 0 \dots . ((i) \frac{x - 5}{4} + \frac{x - 0}{4} + \frac{x - 10 - y}{1} = 0 x - 5 + x + 4 x - 40 - 4 y = 0 6 x - 4 y - 45 = 0 .. (i) \frac{- 2 x + 4 y + 15 = 0.. ( ii )}{4 x - 30 = 0} x = \frac{15}{2} &4 y - 15 + 15 = 0 y = 0 i = \frac{y - x + 10}{1} i = \frac{0 - 7.5 + 10}{1} i = 2.5 A = \frac{n}{10} A n = 25$

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Circuit Analysis

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