A moving coil galvanometer allows a full scale current of 1 0 − 4 A . A series resistance of 2 × 1 0 4 Ω is required to convert the galvanometer into a voltmeter of range 0 − 5 V . Therefore, the valu

Question

A moving coil galvanometer allows a full scale current of 1 0 − 4 A . A series resistance of 2 × 1 0 4 Ω is required to convert the galvanometer into a voltmeter of range 0 − 5 V . Therefore, the value of shunt resistance required to convert the above galvanometer into an ammeter of range 0 − 10 m A is:

TestHub · Accepted Answer

i g ​ = 1 0 − 4 A i = 10 × 1 0 − 3 A R V ​ = 20 k Ω i g ​ G + i g ​ R V ​ = 5 i g ​ G = ( i − i g ​ ) R A ​ R A ​ = i − i g ​ i g ​ G ​ = ( i − i g ​ ) i g ​ i g ​ ( 5 − i g ​ R V ​ ) ​ R A ​ = i − i g ​ 5 − i g ​ R V ​ ​ ≈ 300 Ω

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