Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityCircuit AnalysisHard2 minQB

PhysicsHardinteger

Find the potential difference $V_{B} - V_{A}$

for the circuit shown in the figure. If the answer is

\frac{x}{y}

write value of

x + y

Answer:

Solution:

$\frac{x + 4 - 4}{1} + \frac{( x + 3 - 4 )}{1} + \frac{x}{1} + \frac{( x + 2 - 3 )}{1} + \frac{x}{1} + \frac{x + 1 - 2}{1} + \frac{x}{1} + \frac{x - 1}{1} + \frac{x}{1} = 0$

$5 x + 4 (x - 1) = 0$ $9 x - 4 = 0$

$x = \frac{4}{9} V$

$V_{B} - V_{A} = (x + 2 - 0) = \frac{22}{9} V$

Stream:BoardsSubject:PhysicsTopic:Current ElectricitySubtopic:Circuit Analysis

⏱ 2mℹ️ Source: QB

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