Two cells are connected in opposition as shown. Cell $E_{1}$ is of $8 V$ emf and $2 Ω$ internal resistance; the cell $E_{2}$ is of $2 V$ emf and $4 Ω$ internal resistance. The terminal potential difference of cell $E_{2}$ is ______ $V$ .

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Current in circuit, I = 8 - 2 2 + 4 = 6 6 = 1 A Applying Kirchhoff's law from C to B , V C - 2 - 4 × 1 = V B ⇒ V C - V B = 6 V

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