Start Free Mock LoginAlready registered? Login here

Physics - Current Electricity Question with Solution | TestHub

PhysicsCurrent ElectricityEquivalent ResistanceMedium2 minQB

PhysicsMediumsingle choice

Two resistors $R_{1} = (4 \pm 0.8) Ω$ and $R_{2} = (4 \pm 0.4) Ω$ are connected in parallel. The equivalent resistance of their parallel combination will be :

Options:

Answer:

Solution:

$\frac{Δ R}{R ^{2}} = \frac{Δ R _{1}}{R _{1}^{2}} + \frac{Δ R _{2}}{R _{2}^{2}}$
$Δ R = (R)^{2} [\frac{Δ R _{1}}{R _{1}^{2}} + \frac{Δ R _{2}}{R _{2}^{2}}]$
$= (2)^{2} [\frac{0.8}{4 ^{2}} + \frac{0.4}{4 ^{2}}]$
$= [0.2 + 0.1] = 0.3$
$R_{net} = R + Δ R = 2 \pm 0.3$

Stream:JEESubject:PhysicsTopic:Current ElectricitySubtopic:Equivalent Resistance

⏱ 2mℹ️ Source: QB

Doubts & Discussion

Loading discussions...