An electric bulb of 500 W at 100 V is used in a circuit having a 200 V supply. Calculate the resistance R to be connected in series with the bulb so that the power delivered by the bulb is 500 W .

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TestHub · Accepted Answer

Resistance of bulb P = r V 2 ​ r = 500 ( 100 ) 2 ​ = 500 100 × 100 ​ = 20 i = V P ​ = 100 500 ​ = 5 A Δ V in resistance R = 100 V R = 5 100 ​ = 20Ω

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