Physics - Current Electricity Question with Solution | TestHub

Current through the battery is minimum when S2 is open and S1, S3 closed: 6 Ω + (6 Ω + 3 Ω) and 9 Ω branch... equivalent: $R_{eq}=7+\frac{9}{2}+\frac{1}{2}=12\Omega$

$i=\frac{24}{12}=2\mathrm{Amp}$

$V_{AB}=R_{AB}\times i_{AB}=1\times \frac{i}{2}=1\times \frac{2}{2}=1\mathrm{volt}$